Как происходит окисление толуола в нейтральной среде с помощью KMnO4?
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Ответ создан на основе результатов поиска
Окисление толуола в нейтральной среде с помощью KMnO4 происходит с образованием калиевой соли бензойной кислоты14. Уравнение реакции: C6H5CH3 + 2 KMnO4 = С6H5COOK + 2 MnO2 + KOH + H2O 1.
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[```1```](https://acetyl.ru/?search=ff1a1q1qy60q2&npt=%D1%82%D0%BE%D0%BB%D1%83%D0%BE%D0%BB_plus_KMnO4)[```4```](https://www.youtube.com/watch?v=Ea0Wd4j1NXw). Уравнение реакции: C6H5CH3 + 2 KMnO4 = С6H5COOK + 2 MnO2 + KOH + H2O [```1```](https://acetyl.ru/?search=ff1a1q1qy60q2&npt=%D1%82%D0%BE%D0%BB%D1%83%D0%BE%D0%BB_plus_KMnO4).","sources":[{"sourceId":1,"url":"https://acetyl.ru/?search=ff1a1q1qy60q2&npt=%D1%82%D0%BE%D0%BB%D1%83%D0%BE%D0%BB_plus_KMnO4","title":"Толуол + KMnO4. Возможные реакции. 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